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Basic Electronics » Measuring Capacitance
October 20, 2011 by Etbauer |
I am working on a project and would like to use the HS1101 humidity sensor. In order to do so I have been testing capacitance measurement on the breadboard using the technique in the halloween project. I used the same pinout and setup with a 270K resistor in parallel with a few different known capacitors. In doing so, I took a few measurements:
while each measurement was very consistent over several tries, I'm finding the measurements between each measurement is sort of inconsistent. using Vc = Vs * e^(-t/RC) and t = cycles * 1/14745600 Assuming Vs = 5v (verified using multimeter) and Vc = 1.1v I determined the following:
In other words, I realize there exists stray capacitance in the breadboard, but the difference in calculated capacitance between each capacitor varies from 46 to 27, so it doesn't seem to be the problem, and the variation in clock cycles varies from 164 to 274 which seems like too much to attribute to processing delay, so I am trying to figure out what I am missing. It strikes me as I am writing this that I didnt take care to ensure that each pin went into the same hole on each rail, but to my understanding, that shouldn't matter. So anyway, any illumination on the subject would be appreciated :) thank you all. |
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October 21, 2011 by Ralphxyz |
Hi Etbauer, are you building a weather station? I cannot answer your question it's kinda over my head but I am wondering why you are focusing on capacitance measurement? Besides just learning. The HS1101 humidity sensor has a "PROPORTIONAL VOLTAGE OUTPUT CIRCUIT" that would feed directly to the mcu ADC and also a "FREQUENCY OUTPUT CIRCUITS" that the mcu could monitor. You do not need to measure capacitance so I am just wondering what exactly are you focusing on. It's very easy to get off on a tangent in this business. Ralph |
October 21, 2011 by Etbauer |
Hey Ralph, thanks for the reply, I am actually trying to build an incubator for chicken eggs. If I understand the datasheet correctly, the Proportional voltage can be generated through a seperate circuit which would require building a few oscillators, a low pass filter etc, so it seems much simpler and more economical to measure the capacitance directly. While I would be interested in learning more about how to measure the capacitance with proportional oscillators and frequency output circuits, I am mostly concerned at this point with what is wrong with my assumptions using the current design. |
October 22, 2011 by Ralphxyz |
In looking at parallex specsheet quickly I thought you could just use the proportional voltage without external components. This specsheet from Jameco is a little better and actually gives you a useable circuit. All you would need is a counter on the mcu, you would not need a oscillator (555) just count the RCTIME pulse (frequency). It is strange but I think Vss would be 5v + to the Ground pin. Amongst my many project I have been working on is a weather station and I blew my I2C humidity sensor and need to replace it so maybe this would work. Ralph |
October 22, 2011 by Etbauer |
Hey Ralph, yeah this is actually what i was doing, my circuit is the same (and same as the pumpkin circuit here on NK). The only difference is that I don't have the 220 resistor, and the 10M resistor is a 270k. Vss is the ground, it is referencing the source voltage of an n-channel FET. i got a hygrometer today, and using that i can sort of calibrate and go from there, i still wonder where that variation is coming from, it would be nice to be able to calculate mathematically where the humidity is. Though for this project I really only need a small range of humidity sensing. |
October 22, 2011 by Ralphxyz |
One of these days I'll have to look at the pumpkin circuit, right now I am lost on what is the power source if Vss is ground and the mcu is reading frequency. Maybe I'd understand the 555 circuit better. Ralph |
October 22, 2011 by Etbauer |
well the power source would be Vdd, for the drain, if you look at the capacitor in the circuit, you can see that the positive side is connected to the pin, and the negative side has to be connected to the ground, essentially you turn the pin on and fill the capacitor, then turn it off and set it to an input then time how long until the voltage drops below teh input threshold |
October 23, 2011 by BobaMosfet |
yep- essentially a clever way to make a 1 cycle oscillation. There's no magic here, it's a capacitor. BM |
October 24, 2011 by Ralphxyz |
Now that's neat!! I was having problems powering the circuit now that makes sense. Of course I want to see the code that does that. Ralph |
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